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Last updated: Sat, 27 Jan 2007

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# str_word_count

(PHP 4 >= 4.3.0, PHP 5)

str_word_count -- Возвращает информацию о словах, входящих в строку

## Описание

mixed str_word_count ( string string [, int format] )

Подсчитывает количество слов, входящих в строку `string`. Если необязательный аргумент `format` не передан, возвращается целое число, равное количеству слов. В случае, если аргумент `format` передан, возвращается массив, содержимое которого зависит от значения этого аргумента. Ниже описаны допустимые значения аргумента `format` и соответствующие им возвращаемые значения.

- 1 - возвращается массив, содержащий все слова, входящие в строку `string`.

- 2 - возвращается массив, индексами которого являются позиции в строке, а значениями - соответствующие слова.

Эта функция считает словами последовательности алфавитных символов, возможно, включающие, но не начинающихся с "'" и "-". Набор символов, считающихся алфавитными, зависит от текущей локали.

Пример 1. Пример использования str_word_count()

`<?php
$str = "Hello friend, you're
looking good today!";
$a = str_word_count($str, 1);
$b = str_word_count($str, 2);
$c = str_word_count($str);
print_r($a);
print_r($b);
echo $c;
?>`

Вывод:

    Array
    (
        [0] => Hello
        [1] => friend
        [2] => you're
        [3] => looking
        [4] => good
        [5] => today
    )

    Array
    (
        [0] => Hello
        [6] => friend
        [14] => you're
        [29] => looking
        [46] => good
        [51] => today
    )

    6

См. также описание функций explode(), preg_split(), split(), count_chars() и substr_count().

add a note User Contributed Notes
str_word_count
joshua dot blake at gmail dot com
02-Mar-2007 05:02
`I needed a function which would extract the first hundred words out of a given input while retaining all markup such as line breaks, double spaces and the like. Most of the regexp based functions posted above were accurate in that they counted out a hundred words, but recombined the paragraph by imploding an array down to a string. This did away with any such hopes of line breaks, and thus I devised a crude but very accurate function which does all that I ask it to:
function Truncate($input, $numWords)
{
if(str_word_count($input,0)>$numWords)
{
$WordKey = str_word_count($input,1);
$PosKey = str_word_count($input,2);
reset($PosKey);
foreach($WordKey as $key => &$value)
{
$value=key($PosKey);
next($PosKey);
}
return substr($input,0,$WordKey[$numWords]);
}
else {return $input;}
}
The idea behind it? Go through the keys of the arrays returned by str_word_count and associate the number of each word with its character position in the phrase. Then use substr to return everything up until the nth character. I have tested this function on rather large entries and it seems to be efficient enough that it does not bog down at all.
Cheers!
Josh`
josh at joshblake.net
01-Mar-2007 03:57
`I was interested in a function which returned the first few words out of a larger string.
In reality, I wanted a preview of the first hundred words of a blog entry which was well over that.
I found all of the other functions which explode and implode strings to arrays lost key markups such as line breaks etc.
So, this is what I came up with:
function WordTruncate($input, $numWords) {
if(str_word_count($input,0)>$numWords)
{
$WordKey = str_word_count($input,1);
$WordIndex = array_flip(str_word_count($input,2));
return substr($input,0,$WordIndex[$WordKey[$numWords]]);
}
else {return $input;}
}
While I haven't counted per se, it's accurate enough for my needs. It will also return the entire string if it's less than the specified number of words.
The idea behind it? Use str_word_count to identify the nth word, then use str_word_count to identify the position of that word within the string, then use substr to extract up to that position.
Josh.`
30-Jan-2007 08:15
`Here is a php work counting function together with a javascript version which will print the same result.
<?php
//Php word counting function
function word_count($theString)
{
$char_count = strlen($theString);
$fullStr = $theString." ";
$initial_whitespace_rExp = "^[[:alnum:]]$";
$left_trimmedStr = ereg_replace($initial_whitespace_rExp,"",$fullStr);
$non_alphanumerics_rExp = "^[[:alnum:]]$";
$cleanedStr = ereg_replace($non_alphanumerics_rExp," ",$left_trimmedStr);
$splitString = explode(" ",$cleanedStr);
$word_count = count($splitString)-1;
if(strlen($fullStr)<2)
{
$word_count=0;
}
return $word_count;
}
?>
<?php
//Function to count words in a phrase
function wordCount(theString)
{
var char_count = theString.length;
var fullStr = theString + " ";
var initial_whitespace_rExp = /^[^A-Za-z0-9]+/gi;
var left_trimmedStr = fullStr.replace(initial_whitespace_rExp, "");
var non_alphanumerics_rExp = rExp = /[^A-Za-z0-9]+/gi;
var cleanedStr = left_trimmedStr.replace(non_alphanumerics_rExp, " ");
var splitString = cleanedStr.split(" ");
var word_count = splitString.length -1;
if (fullStr.length <2)
{
word_count = 0;
}
return word_count;
}
?>`
Aurelien Marchand
06-Oct-2006 09:06
`I found a more reliable way to print, say the first 100 words and then print elipses. My code goes this way;
$threshold_length = 80; // 80 words max
$phrase = "...."; // populate this with the text you want to display
$abody = str_word_count($phrase,2);
if(count($abody) >= $threshold_length){ // gotta cut
$tbody = array_keys($abody);
echo "<p>" . substr($phrase,0,$tbody[$threshold_length]) . "... <span class=\"more\"><a href=\"?\">read more</a></span> </p>\n";
} else { // put the whole thing
echo "<p>" . $phrase . "</p>\n";
}
For any questions, com.iname@artaxerxes2`
lwright at psu dot edu
17-Aug-2006 11:51
`If you are looking to count the frequency of words, try:
<?php
$wordfrequency = array_count_values( str_word_count( $string, 1) );
?>`
rabin at rab dot in
04-Apr-2006 11:03
`There is a small bug in the "trim_text" function by "webmaster at joshstmarie dot com" below. If the string's word count is lesser than or equal to $truncation, that function will cut off the last word in the string.
[EDITOR'S NOTE: above referenced note has been removed]
This fixes the problem:
<?php
function trim_text_fixed($string, $truncation = 250) {
$matches = preg_split("/\s+/", $string, $truncation + 1);
$sz = count($matches);
if ( $sz > $truncation ) {
unset($matches[$sz-1]);
return implode(' ',$matches);
}
return $string;
}
?>`
webmaster at joshstmarie dot com
25-Sep-2005 04:58
`Trying to make an effiecient word splitter, and "paragraph limiter", eg, limit item text to 100, or 200 words and so-forth.
I don't know how well this compares, but it works nicely.
function trim_text($string, $word_count=100)
{
$trimmed = "";
$string = preg_replace("/\040+/"," ", trim($string));
$stringc = explode(" ",$string);
echo sizeof($stringc);
if($word_count >= sizeof($stringc))
{
// nothing to do, our string is smaller than the limit.
return $string;
}
elseif($word_count < sizeof($stringc))
{
// trim the string to the word count
for($i=0;$i<$word_count;$i++)
{
$trimmed .= $stringc[$i]." ";
}
if(substr($trimmed, strlen(trim($trimmed))-1, 1) == '.')
return trim($trimmed).'..';
else
return trim($trimmed).'...';
}
}
$text = "some test text goes in here, I'm not sure, but ok.";
echo trim_text($text,5);`
MadCoder
15-Aug-2005 09:12
`Here's a function that will trim a $string down to a certian number of words, and add a... on the end of it.
(explansion of muz1's 1st 100 words code)
----------------------------------------------
function trim_text($text, $count){
$text = str_replace(" ", " ", $text);
$string = explode(" ", $text);
for ( $wordCounter = 0; $wordCounter <= $count;wordCounter++ ){
$trimed .= $string[$wordCounter];
if ( $wordCounter < $count ){ $trimed .= " "; }
else { $trimed .= "..."; }
}
$trimed = trim($trimed);
return $trimed;
}
Usage
------------------------------------------------
$string = "one two three four";
echo trim_text($string, 3);
returns:
one two three...`
jtey at uoguelph dot ca
14-Aug-2005 04:21
`In the previous note, the example will only extract from the string, words separated by exactly one space. To properly extract words from all strings, use regular expressions.
Example (extracting the first 4 words):
<?php
$string = "One two three four five six";
echo implode(" ", array_slice(preg_split("/\s+/", $string), 0, 4));
?>
The above $string would not have otherwise worked when using the explode() method below.`
jtey at uoguelph dot ca
14-Aug-2005 07:59
`In reply to muz1's post below:
You can also take advantage of using other built in PHP functions to get to your final result. Consider the following:
<?php
$string = "One two three four five six seven eight nine ten.";
// the first n words to extract
$n = 3;
// extract the words
$words = explode(" ", $string);
// chop the words array down to the first n elements
$firstN = array_slice($words, 0, $n);
// glue the 3 elements back into a spaced sentence
$firstNAsAString = implode(" ", $firstN);
// display it
echo $firstNAsAString;
?>
Or to do it all in one line:
<?php
echo implode(" ", array_slice(explode(" ", $string), 0, $n));
?>`
muz1 at muzcore dot com
12-Aug-2005 12:56
`This function is awesome however I needed to display the first 100 words of a string. I am submitting this as a possible solution but also to get feedback as to whether it is the most efficient way of doing it.
<?
$currString = explode(" ", $string);
for ($wordCounter=0; $wordCounter<100; $wordCounter++) { echo $currString[$wordCounter]." "; }
?>`
16-Jan-2005 06:38
`This function seems to view numbers as whitespace. I.e. a word consisting of numbers only won't be counted.`
aix at lux dot ee
14-Nov-2004 02:53
`One function.
<?php
if (!function_exists('word_count')) {
function word_count($str,$n = "0"){
$m=strlen($str)/2;
$a=1;
while ($a<$m) {
$str=str_replace(" "," ",$str);
$a++;
}
$b = explode(" ", $str);
$i = 0;
foreach ($b as $v) {
$i++;
}
if ($n==1) return $b;
else return $i;
}
}
$str="Tere Tartu linn";
$c = word_count($str,1); // it return an array
$d = word_count($str); // it return int - how many words was in text
print_r($c);
echo $d;
?>`
aidan at php dot net
26-Jun-2004 03:02
`This functionality is now implemented in the PEAR package PHP_Compat.
More information about using this function without upgrading your version of PHP can be found on the below link:
http://pear.php.net/package/PHP_Compat`
Kirils Solovjovs
22-Feb-2004 09:06
`Nothing of this worked for me. I think countwords() is very encoding dependent. This is the code for win1257. For other layots you just need to redefine the ranges of letters...
<?php
function countwords($text){
$ls=0;//was it a whitespace?
$cc33=0;//counter
for($i=0;$i<strlen($text);$i++){
$spstat=false; //is it a number or a letter?
$ot=ord($text[$i]);
if( (($ot>=48) && ($ot<=57)) || (($ot>=97) && ($ot<=122)) || (($ot>=65) && ($ot<=90)) || ($ot==170) ||
(($ot>=192) && ($ot<=214)) || (($ot>=216) && ($ot<=246)) || (($ot>=248) && ($ot<=254)) )$spstat=true;
if(($ls==0)&&($spstat)){
$ls=1;
$cc33++;
}
if(!$spstat)$ls=0;
}
return $cc33;
}
?>`
Artimis
15-Oct-2003 02:32
`Never use this function to count/separate alphanumeric words, it will just split them up words to words, numbers to numbers. You could refer to another function "preg_split" when splitting alphanumeric words. It works with Chinese characters as well.`
andrea at 3site dot it
19-May-2003 04:55
`if string doesn't contain the space " ", the explode method doesn't do anything, so i've wrote this and it seems works better ... i don't know about time and resource
<?php
function str_incounter($match,$string) {
$count_match = 0;
for($i=0;$i<strlen($string);$i++) {
if(strtolower(substr($string,$i,strlen($match)))==strtolower($match)) {
$count_match++;
}
}
return $count_match;
}
?>
example
<?php
$string = "something:something!!something";
$count_some = str_incounter("something",$string);
// will return 3
?>`
megat at megat dot co dot uk
18-Apr-2003 06:29
`[Ed: You'd probably want to use regular expressions if this was the case --alindeman @ php.net]
Consider what will happen in some of the above suggestions when a person puts more than one space between words. That's why it's not sufficient just to explode the string.`
olivier at ultragreen dot net
11-Apr-2003 06:10
`I will not discuss the accuracy of this function but one of the source codes above does this.
<?php
function wrdcnt($haystack) {
$cnt = explode(" ", $haystack);
return count($cnt) - 1;
}
?>
That could be replace by
<?php
function wrdcnt($haystack) {
return substr_count($haystack,' ') + 1;
}
?>
I doubt this does need to be a function :)`
philip at cornado dot com
06-Apr-2003 07:30
`Some ask not just split on ' ', well, it's because simply exploding on a ' ' isn't fully accurate. Words can be separated by tabs, newlines, double spaces, etc. This is why people tend to seperate on all whitespace with regular expressions.`
rcATinterfacesDOTfr
16-Jan-2003 07:58
`Here is another way to count words :
$word_count = count(preg_split('/\W+/', $text, -1, PREG_SPLIT_NO_EMPTY));`
brettNOSPAM at olwm dot NO_SPAM dot com
09-Nov-2002 12:06
`This example may not be pretty, but It proves accurate:
<?php
//count words
$words_to_count = strip_tags($body);
$pattern = "/[^(\w|\d|\'|\"|\.|\!|\?|;|,|\\|\/|\-\-|:|\&|@)]+/";
$words_to_count = preg_replace ($pattern, " ", $words_to_count);
$words_to_count = trim($words_to_count);
$total_words = count(explode(" ",$words_to_count));
?>
Hope I didn't miss any punctuation. ;-)`
gorgonzola at nospam dot org
31-Oct-2002 02:48
`i tried to write a wordcounter and ended up with this:
<?php
//strip html-codes or entities
$text = strip_tags(strtr($text, array_flip(get_html_translation_table(HTML_ENTITIES))));
//count the words
$wordcount = preg_match_all("#(\w+)#", $text, $match_dummy );
?>`
add a note
strcasecmp str_split

Last updated: Sat, 27 Jan 2007
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