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# mysql_affected_rows

(PHP 3, PHP 4, PHP 5)

mysql_affected_rows -- Возвращает число затронуиых прошлой операцией рядов.

## Описание

int mysql_affected_rows ( [resource link_identifier] )

mysql_affected_rows() возвращает количество рядов, затронутых последним INSERT, UPDATE, DELETE запросом к серверу, на который ссылается указатель `link_identifier`. Если ресурс не указан, функция использует последнее, успешное соединение, выполненное с помощью функции mysql_connect().

> Замечание: При использовании транзакций mysql_affected_rows() надо вызывать после INSERT, UPDATE, DELETE запроса, но не после подтверждения.

Если последний запрос был DELETE без указания WHERE и, соответственно, таблица была очищена, функция вернёт ноль (0).

> Замечание: При использовании UPDATE, MySQL не обновит колонки, уже содержащие новое значение. Вследствие этого, функция mysql_affected_rows() не всегда возвращает количество рядов, подошедших по условия, только количество рядов, обновлённых запросом.

mysql_affected_rows() не работает с SELECT -- только с запросами, модифицирующими таблицу. Чтобы получить количество рядов, возвращённых SELECT-запросом, используйте функцию mysql_num_rows().

Если последний запрос был неудачным, функция вернёт -1.

Пример 1. DELETE-запрос

`<?php
/* соединямеся с базой данных */
mysql_pconnect("localhost", "mysql_user", "mysql_password") or
die("Could not connect: " . mysql_error());
mysql_select_db("mydb");
/* здесь функция вернёт корректное число удалённых записей */
mysql_query("DELETE FROM mytable WHERE id < 10");
printf ("Records deleted: %d\n", mysql_affected_rows());
/* без указания WHERE в запросе, функция всегда возвращает 0 */
mysql_query("DELETE FROM mytable");
printf ("Records deleted: %d\n", mysql_affected_rows());
?>`

Вышеописанный пример выдаст следующий результат:

    Records deleted: 10
    Records deleted: 0

Пример 2. UPDATE-запрос

`<?php
/* соединямеся с базой данных */
mysql_pconnect("localhost", "mysql_user", "mysql_password") or
die("Could not connect: " . mysql_error());
mysql_select_db("mydb");
/* Обновляем ряды */
mysql_query("UPDATE mytable SET used=1 WHERE id < 10");
printf ("Updated records: %d\n", mysql_affected_rows());
mysql_query("COMMIT");
?>`

Вышеописанный пример выдаст следующий результат:

    Updated Records: 10

См. также mysql_num_rows(), mysql_info().

add a note User Contributed Notes
mysql_affected_rows
mlugassy at 2find dot co dot il
07-Oct-2005 06:22
`To solve the affectedRows() issue on MySQL using PEAR::DB, simply add a 'client_flags' key with a value of 2 to your $dsn options:
$dsn = array(
'phptype' => 'mysql',
'client_flags' => 2,
'username' => 'someuser',
'password' => 'apasswd',
'hostspec' => 'localhost',
'database' => 'thedb',
);`
temp02 at flexis dot com dot br
29-Jun-2005 05:39
`SCENARIO
1. You're using MySQL 4.1x with foreign keys.
2. You have table t2 linked to table t1 by a CASCADE ON DELETE foreign key.
3. t2 has a UNIQUE key so that duplicate records are unacceptable.
3. You have a REPLACE query on t1 followed by an INSERT query on t2 and expect the second query to fail if there's an attempted insert of a duplicate record.
PROBLEM
You notice that the second query is not failing as you had expected even though the record being inserted is an exact duplicate of a record previously inserted.
CAUSE
When the first query (the REPLACE query) deletes a record from t1 in the first stage of the REPLACE operation, it cascades the delete to the record that would be duplicated in t2. The second query then does not fail because the "duplicate" record is no longer a duplicate, as the original one has just been deleted.`
jeroen_vde at hotmail dot com
12-Mar-2005 05:22
`If you want to delete all in table, and get number of affected rows back use a delete statment of this form:
mysql> DELETE FROM table_name WHERE 1>0;
Note that this is much slower than DELETE FROM table_name with no WHERE clause, because it deletes rows one at a time.
Source: MySQL Reference Manual "Delete Syntax"`
steffen at showsource dot dk
28-Sep-2004 03:20
`Using OPTIMIZE TABLE will also return true.
So, if you want to check the numbers of deleted records, use mysql_affected_rows() before OPTIMIZE TABLE`
sam_dot_fullman_at_verizon.nt
19-May-2004 12:12
`Just a MySQL note, using REPLACE INTO on a record could return either ONE or TWO affected rows with this function. Basically, REPLACE INTO will insert a record if no combination of unique keys is matched, or delete the existing record if the new record matches one or more unique keys, then insert the new record over it.
This is actually helpful if you want to know if a record was already in there. (Affected rows=1 means there wasn't already a record there, Affected rows=2 means there was), but if you don't know how REPLACE INTO works it could confuse you. I didn't see this in the notes above and hope it helps someone out.`
deponti A_T tiscalinet D0T it
07-Nov-2003 04:52
`It works also for REPLACE query,returning:
0 if the record it's already updated (0 record modified),
1 if the record it's new (1 record inserted),
2 if the record it's updated (2 operations: 1 deletion+ 1 insertion)`
Richard dot Johnson2 at student dot gu dot edu dot au
25-Oct-2003 03:56
`RE: sng2nara's comment
I think the expression should read:
"/^[^0-9]+([0-9]+)[^0-9]+([0-9]+)[^0-9]+([0-9]+).*$/"
as there is nothing usually returned after the number of warnings. The previous expression required at least 1 non-digit character after the number of warnings.`
sng2nara
02-Oct-2003 12:41
`You can use following code for choosing update or insert.
mysql_query($update_sql);
preg_match(
"/^[^0-9]+([0-9]+)[^0-9]+([0-9]+)[^0-9]+([0-9]+)[^0-9]+$/",
mysql_info(),
$arr);
if( $arr[1] == 0 ) // a number of matched rows is 0
{...do insert query...}
else
{...nothing...}`
raistlin at oracolo dot com
03-Jul-2003 09:38
`| If you need to know the actual count of rows,
| even if some update changed nothing add a field
| count int(11) and add | one on every update, like in:
|
| mysql_query("update table set count=count+1, ...");
| if (mysql_affected_rows()==0) {
| mysql_query("insert into table ...");
| }
Better: add a field `flag` tinyint(1) unsigned default '0'
on every update: "update table set flag=1-flag, ..."`
anthonyd at rhsonline dot net
02-Jul-2003 04:08
`My little work around for the update problem (that I ran into):
if (mysql_affected_rows()==0) {
$q = "select .. WHERE ...<search for what you updated>'";
if (mysql_num_rows(mysql_query($q))==0)
die("0 rows affected");
else
echo "Record Alredy Existed";
}
It is probably not the best way, as I sometimes run 2 queries for the same thing, but it gets the job done.`
phpweb at eden2 dot com
27-Jun-2003 11:47
`"Note: When using UPDATE, MySQL will not update columns where the new value is the same as the old value. This creates the possiblity that mysql_affected_rows() may not actually equal the number of rows matched, only the number of rows that were literally affected by the query."
As of PHP 4.3.0 (I assume, I only tried with 4.3.2), you can make mysql_affected_rows() return the number of rows matched, even if none are updated.
You do this by setting the CLIENT_FOUND_ROWS flag in mysql_connect(). For some reason, not all the flags are defined in PHP, but you can use the decimal equivalent, which for CLIENT_FOUND_ROWS is 2.
So, for example:
$db= mysql_connect("localhost", "user", "pass", false, 2);
mysql_select_db("mydb", $db);
$query= "UPDATE ...";
mysql_query($query);
print mysql_affected_rows(); // more than 0
mysql_query($query); // same query twice
print mysql_affected_rows(); // still more than 0`
gabriel dot preda at amr dot ro
18-Jun-2003 08:35
`-1-----------------------------
$w = "insert into...";
$q = mysql_query($w) or die('mortua est'); // 1433 times
print mysql_affected_rows($cnex); // prints 1433
-2-----------------------------
$w = "insert into...";
$q = mysql_query($w) or die('mortua est'); // 1433 times
@mysql_query("SELECT a FROM b LIMIT x"); //
print mysql_affected_rows($cnex); // prints x
It appears that php's "mysql_affected_rows" calls mysql's "mysql_affected_rows"... witch says:
"For SELECT statements, mysql_affected_rows() works like mysql_num_rows().
mysql_affected_rows() is currently implemented as a macro."`
adam at NOSPAM dot example dot com
17-Jan-2003 11:34
`using PHP/MySql -There is an alternate way to get the rows returned -
for non-critical use i suppose--due to its oversimplified approach.
You can simply intialize a variable to the integer value of 0, and then, inside of the "while" loop that returns the rows
of your query, you increment that variable and then print out the final value of that variable outside of that "while" loop.
Or, you could print the variable within each iteration if you want to give each row returned [ as in a chart where you
need to provide line numbers ]
//code:
$sql = "SELECT * FROM YourTable
ORDER BY Last_Name";
$result = @mysql_query($sql, $connection) or die("Could not execute query.");
$i = 0; // we will use variable $i as a returned row counter.
while ($row = mysql_fetch_array($result)) {
$First_Name = $row['First_Name'];
$Last_Name = $row['Last_Name'];
$num_rows = mysql_num_rows($result);
$i++;
//To show the rows number by number
echo "Member no. $i $First_Name $Last_Name < br >";
// the < br > is an actual HTML line break
// which is not allowed on posting these notes,
// to use it, close up the spaces between the < and the >
// above echo statement will produce the results below if 3 rows were returned:
// Member no. 1 John Jones
// Member no. 2 Mary Smith
// Member no. 3 Nancy Steffan
}
echo "$i Rows Returned from query.";
// above statement will produce:
// 3 Rows Returned from query.
Hope this helps-- again,
this is a simplified approach.
take care;
<?adam?>`
spam123 at cobsen dot biz
08-Dec-2002 05:04
`If you need to know the actual count of rows, even if some update changed nothing add a field count int(11) and add one on every update, like in:
mysql_query("update table set count=count+1, ...");
if (mysql_affected_rows()==0) {
mysql_query("insert into table ...");
}`
ben-xo at NOSPAMdubplatesNOSPAM dot org
21-Apr-2002 07:30
`mysql_affected_rows() reports on the number of rows affected by an in-place operation on the database, but mysql_num_rows() returns the number of rows in a MySQL record set (which is held by PHP after MySQL has generated it). This means that if you can do
$a = mysql_query("SELECT ...");
$b = mysql_query("SELECT ...");
if (mysql_unm_rows($a) > mysql_num_rows($b)) print "a is larger";
else print "b is larger";
... but this does not make sense for the operations supported by mysql_affected_rows(), which reports on the status of the database connection as a whole.
Particularly note this:
$query = "UPDATE ...";
mysql_query($query);
print mysql_affected_rows(); // more than 0
mysql_query($query); // same query twice
print mysql_affected_rows(); // 0.
.. this is because the 2nd time you execute the identical query, all the rows are already updated so no rows are affected the 2nd time.
I hope this clears up why mysql_num_rows() and mysql_affected_rows() are fundamentally different`
dfylstra at frontsys dot com
13-Aug-2001 12:06
`mysql_affected_rows() also reports the number of rows changed by the LOAD DATA command. If you use the IGNORE option in LOAD DATA and you know the number of rows in the input file, you can use mysql_affected_rows() to determine the number of rows that were ignored.`
peter at petermoulding dot NO_SPAM dot com
05-Aug-2001 11:34
`mysql_affected_rows() fails with some automatic updates. An example from the PHP Black Book is that of session records updated by automatic timestamps. When you maintain the session valid time via a timestamp and use some databases including MySQL, then update the session record, the automatic timestamp update will not count as an update in mysql_affected_rows(). You have to manually update the timestamp field. In MySQL that is achieved by setting the field to nulls. If your time field is named updated, you have to include
set updated = null
Other databases require appropriate tricks and you will have to test stored procedures in your database to see if their updates count in mysql_affected_rows().`
add a note
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Last updated: Sat, 27 Jan 2007
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