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Last updated: Fri, 26 Jan 2007

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# mcal_date_compare

(PHP 3 >= 3.0.13, PHP 4, PECL)

mcal_date_compare -- Compares two dates

## Description

int mcal_date_compare ( int a_year, int a_month, int a_day, int b_year, int b_month, int b_day )

mcal_date_compare() Compares the two given dates, returns <0, 0, >0 if a<b, a==b, a>b respectively.

add a note User Contributed Notes
mcal_date_compare
asharm4 at ilstu dot edu
14-Sep-2005 08:41
`//this function compares any date to current date and returns results in form of integers..
function date_compare ( $b_year, $b_month, $b_day )
{
$a_year = $today["year"];
$a_month = $today["mon"];
$a_day = $today["mday"];
$final_result = 9; //set it to random right now
if($a_year >$b_year)
{
$final_result = 1; //the year 1 is greater then year 2 so no more check required
}//year greater
else if($a_year == $b_year) //the years are the same ..so check the month
{
if($a_month > $b_month)
{
$final_result = 2; //the months are greater and so no more checks needed
}//greater month check
else
if($a_month == $b_month)//same months ..so check dates
{
if($a_day > $b_day)
{
$final_result = 3; //the days solve the problem :)
}
else if($a_day == $b_day)
{
$final_result = 4; //the dates are identical too..so date1 becomes equal to date 2
}
else
{
$final_result = -3; //the date1 < $date 2
}
}//equal month check
else
{
$final_result = -2;
}//month1 < month2
}//year same
else
{
$final_result = -1; //the year 1 is smaller then year 2 ..hence date1 < date2
}
return $final_result;
}`
asharm4 at ilstu dot edu
14-Sep-2005 08:25
`//function to compare existing date from database to the current date
$check_array_deadline = explode("/", "08/24/2005");//this date is from database and in the format mm/dd/yyyy
$a_year = $today["year"];
$a_month = $today["mon"];
$a_day = $today["mday"];
$b_year = $check_array_deadline[2];
$b_month = $check_array_deadline[0];
$b_day = $check_array_deadline[1];
$check_date = date_compare( $a_year, $a_month, $a_day, $b_year, $b_month, $b_day );
function date_compare ( $a_year, $a_month, $a_day, $b_year, $b_month, $b_day )
{
$final_result = 9; //set it to random right now
if($a_year >$b_year)
{
$final_result = 1; //the year 1 is greater then year 2 so no more check required
}//year greater
else if($a_year == $b_year) //the years are the same ..so check the month
{
if($a_month > $b_month)
{
$final_result = 2; //the months are greater and so no more checks needed
}//greater month check
else
if($a_month == $b_month)//same months ..so check dates
{
if($a_day > $b_day)
{
$final_result = 3; //the days solve the problem :)
}
else if($a_day == $b_day)
{
$final_result = 4; //the dates are identical too..so date1 becomes equal to date 2
}
else
{
$final_result = -3; //the date1 < $date 2
}
}//equal month check
else
{
$final_result = -2;
}//month1 < month2
}//year same
else
{
$final_result = -1; //the year 1 is smaller then year 2 ..hence date1 < date2
}
return $final_result;
}`
add a note
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Last updated: Fri, 26 Jan 2007
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