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Last updated: Sat, 27 Jan 2007

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# next

(PHP 3, PHP 4, PHP 5)

next -- Передвинуть внутренний указатель массива на одну позицию вперёд

## Описание

mixed next ( array &array )

Возвращает значение элемента массива, находящегося на позиции, следующей за позицией, в которой находится его внутренний указатель или `FALSE`, если достигнут конец массива.

next() ведёт себя подобно current(), но с одним отличием. Перед тем, как возвратить значение элемента массива, эта функция передвигает его внутренний указатель на одну позицию вперёд. Другими словами, она возвращает следующий элемент массива и сдвигает его внутренний указатель на одну позицию. Если при продвижении внутренний указатель массива выйдет за предел списка элементов, next() возвратит `FALSE`.

Внимание
Если массив содержит пустые или равные 0 элементы, функция возвратит `FALSE` для этих элементов. Для того, чтобы правильно просматривать массивы, содержащие пустые элементы, используйте функцию each().

Пример 1. Пример использования next() и друзей

`<?php
$transport = array('foot', 'bike', 'car', 'plane');
$mode = current($transport); // $mode = 'foot';
$mode = next($transport); // $mode = 'bike';
$mode = next($transport); // $mode = 'car';
$mode = prev($transport); // $mode = 'bike';
$mode = end($transport); // $mode = 'plane';
?>`

См. также current(), end(), prev() и reset().

add a note User Contributed Notes
next
deadimp at gmail dot com
07-Feb-2007 09:08
`There ought to be some sort of peek function, like an i/o stream in C/C++...
I've looked through the documentation here, but I haven't found anything.
A simple implementation:
<?php
function peek(&$array) { //Peek to next element on array stack
$ret=next($array);
prev($array);
return $ret;
}
?>
I'm not sure if there should be any more references with $ret (for efficiency).
I'm using this to see if it's the last element on the stack.
<?php
foreach ($array as $a) {
...
if (peek($array)!==false) ...;
}
?>
Useful for extended implode-type functionality.`
gg2005 at gmail dot com
06-Feb-2007 01:32
`Don't confuse next with continue!
If you're a Perl developer starting with PHP, you might try to use "next" inside a loop to skip to the next iteration...
i.e.,
foreach ($things as $thing) {
if (something I don't like about $thing) {
next;
}
blah....
}
The php compiler will take next... but it's not going to work.
Do this instead:
foreach ($things as $thing) {
if (something I don't like about $thing) {
continue;
}
blah....
}`
GPatmore
12-Oct-2006 12:14
`If your using a foreach loop, unless you for a reference, PHP will make a copy of the array to use it the loop.
So, when I need to take a different action for the last element in the array I use the following:
<?php
$ary = explode(',','a,b,c,d,e,f,g');
foreach($ary as $a){
print 'letter ' . $a;
if(next($ary)){
print '<br>';
}else{
print '<br>dun!';
}
}
?>
Output:
letter a
letter b
letter c
letter d
letter e
letter f
letter g
dun!
NOTE::
PHP5 has added an ability to reference the variable in a foreach like:
<?php
foreach($ary as &$a){}
?>
this will probably cause undesired results when using the method above.
also if the array is changed in any way as to cause the length of the original array to become different then the copy, it will not work.
Consider the following example:
<?php
$ary = explode(',','a,b,c,d,e,f,g');
foreach($ary as $a){
print 'letter ' . $a;
if(next($ary)){
unset($ary[count($ary) - 1]);
print '<br>';
}else{
print '<br>dun!';
}
}
?>
output:
letter a
letter b
letter c
letter d
dun!letter e
dun!letter f
dun!letter g
dun!`
tom at nono dot be
26-Jul-2006 04:19
`I see some questions like "how can I know if an array has a next value without changing its internal pointer" and some pretty complicated responses that DO work mind you and in some cases you'll need them...
But suppose you just need a different action within a foreach loop when reaching the final item:
(it won't be usefull in every situation, but in most it will)
$numOfItems = count($someArray);
$counter = 0;
foreach ($someArray as $key => value){
$counter += 1;
if ($counter <> $numOfItems){
//here all next items exist
} else {
//final item
}
}`
Sigmar
30-May-2006 03:02
`And if you want to know if there are any array elements in array before given key, you can use this function:
function any_array_keys_before($keyname, &$array) {
if (!is_array($array)) {
return false;
}
if (empty($keyname)) {
return false;
}
$set = false;
$count = 0;
foreach ($array as $key => $value) {
if ($set === false && $key != $keyname) {
$count ++;
} else if ($key == $keyname) {
$set = true;
}
}
return $count > 0 ? true : false;
}`
Sigmar
30-May-2006 02:52
`If you want to check, if there are some more elements in array after given key, you can use the following function:
function more_array_keys($keyname, &$array) {
if (!is_array($array)) {
return false;
}
if (empty($keyname)) {
return false;
}
$set = false;
$count = 0;
foreach ($array as $key => $value) {
if ($set === true) {
$count++;
}
if ($key == $keyname) {
$set = true;
}
}
return $count > 0 ? true : false;
}`
tino at infeon dot com
13-May-2006 08:48
`this may be handy and i didnt know where else to post it.. i need a simple function to cycle through an array i eventually made it into a class so i could have multiple cycles.. if you like it or find it usefull please email me and let me know
class Cycle
{
var $position;
var $dataArray;
var $dataArrayCount;
function Cycle()
{
$this->dataArray = func_get_args();
$this->dataArrayCount = count($this->dataArray);
}
function Display()
{
$this->position = (!isset($this->position) || $this->position >= ($this->dataArrayCount - 1)) ? 0 : $this->position += 1;
return $this->dataArray[$this->position];
}
}
$bgColor = new Cycle('#000000', '#FFFFFF', '#FF0000');
echo $bgcolor->Display();
//returns #000000
echo $bgcolor->Display();
//returns #FFFFFF
echo $bgcolor->Display();
//returns #FF0000
echo $bgcolor->Display();
//returns #000000`
brentimus
28-Apr-2005 10:10
`Papipo's function below is usefull in concept but does not work.
"Since you do not pass the array by reference, its pointer is only moved inside the function."
This is true, but the array you are manipulating in your has_next() function will have it's pointer set to the first element, not the same position as the original array. What you want to do is pass the array to the has_next() function via reference. While in the has_next() function, make a copy of the array to work on. Find out the current pointer position of the original array and set the pointer on the working copy of the array to the same element. Then you may test to see if the array has a "next" element.
Try the followig insetad:
<?php
function has_next(&$array)
{
$A_work=$array; //$A_work is a copy of $array but with its internal pointer set to the first element.
$PTR=current($array);
array_set_pointer($A_work, $PTR);
if(is_array($A_work))
{
if(next($A_work)===false)
return false;
else
return true;
}
else
return false;
}
function array_set_pointer(&$array, $value)
{
reset($array);
while($val=current($array))
{
if($val==$value)
break;
next($array);
}
}
?>`
papipo's gmail account
13-Oct-2004 01:47
`I need to know if an array has more items, but without moving array's internail pointer. Thats is, a has_next() function:
<?php
function has_next($array) {
if (is_array($array)) {
if (next($array) === false) {
return false;
} else {
return true;
}
} else {
return false;
}
}
$array = array('fruit', 'melon');
if (has_next($array)) {
echo next($array);
}
// prints 'melon'
?>
Since you do not pass the array by reference, its pointer is only moved inside the function.
Hope that helps.`
lukasz at karapuda dot com
18-Aug-2004 10:06
`This function will return the previous,next neighbors of an array entry within an associative array. If the specified $key points to the last or first element of the array, the first or last keys of the array will be returned consecutively. This is an improved version of the same function posted earlier.
<?php
function array_neighbor($arr, $key)
{
$keys = array_keys($arr);
$keyIndexes = array_flip($keys);
$return = array();
if (isset($keys[$keyIndexes[$key]-1])) {
$return[] = $keys[$keyIndexes[$key]-1];
}
else {
$return[] = $keys[sizeof($keys)-1];
}
if (isset($keys[$keyIndexes[$key]+1])) {
$return[] = $keys[$keyIndexes[$key]+1];
}
else {
$return[] = $keys[0];
}
return $return;
}
?>`
court shrock
20-May-2004 04:36
`This code returns neighbors of the specified key. The result will be empty if it doesn't have any neighbors. My approach was to use the order of keys to determine neighbors, which is differnet from just getting the next/previous element in an array. Feel free to point out stupidities :)
<?php
function array_neighbor($arr, $key)
{
krsort($arr);
$keys = array_keys($arr);
$keyIndexes = array_flip($keys);
$return = array();
if (isset($keys[$keyIndexes[$key]-1]))
$return[] = $keys[$keyIndexes[$key]-1];
if (isset($keys[$keyIndexes[$key]+1]))
$return[] = $keys[$keyIndexes[$key]+1];
return $return;
}
?>`
bm at ANTISPAM dot solidwave dot com
16-Apr-2004 09:49
`Take care when replacing code using reset()/next() with code using foreach as foreach does not update the array's internal pointer. This means you cannot, say, use next() to skip an element in foreach loop, or use current() within a function to get a reference to the current element. You probably have code depending on this internal pointer and replacing it will be more work than you anticipated.
See http://www.php.net/foreach`
add a note
pos natsort

Last updated: Sat, 27 Jan 2007
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